Find the electric potential at point P due to the grouping of charges at the
other corners of the rectangle. The Coulomb constant is 8.98755 × 109
N · m2/C2 and the acceleration due to gravity 9.8 m/s2
Electric
potential V = k * q /r Volts, where k is coulombs constant and q
is the charge.
Electric potential is a scalar
quantity. So the resultant electric potential
at the point P is the sum of
potentials due to individual charges.
ð
V = V1 + V2 + V3
ð
= k * [ (-7.12 / 0.153) + (7.54 /
0.349) + (11.4/0.381) ] * 10-6
(Assuming that -7.12 µc is on smaller side and
at a distance of
0.153m and
7.54 µc on longer side at 0.349 and
Third charge 11.4 µc at a distance of the
diagonal = 0.381).
ð
V =
8.98755 * 10^9 * [(-45.752) + (21.605) + (29.921) ] * 10-6
= 51.89 * 10^3 Volts
(If 7.12 is on the longer side and 7.54 on
shorter side, the relevant
values may be plugged in and V may be recalculated as
above to get
the answer).
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